replace strings.Split(N) for strings.Cut() or alternatives
Go 1.18 and up now provides a strings.Cut() which is better suited for
splitting key/value pairs (and similar constructs), and performs better:
```go
func BenchmarkSplit(b *testing.B) {
b.ReportAllocs()
data := []string{"12hello=world", "12hello=", "12=hello", "12hello"}
for i := 0; i < b.N; i++ {
for _, s := range data {
_ = strings.SplitN(s, "=", 2)[0]
}
}
}
func BenchmarkCut(b *testing.B) {
b.ReportAllocs()
data := []string{"12hello=world", "12hello=", "12=hello", "12hello"}
for i := 0; i < b.N; i++ {
for _, s := range data {
_, _, _ = strings.Cut(s, "=")
}
}
}
```
BenchmarkSplit
BenchmarkSplit-10 8244206 128.0 ns/op 128 B/op 4 allocs/op
BenchmarkCut
BenchmarkCut-10 54411998 21.80 ns/op 0 B/op 0 allocs/op
While looking at occurrences of `strings.Split()`, I also updated some for alternatives,
or added some constraints; for cases where an specific number of items is expected, I used `strings.SplitN()`
with a suitable limit. This prevents (theoretical) unlimited splits.
Signed-off-by: Sebastiaan van Stijn <github@gone.nl>
This commit is contained in:
@@ -128,12 +128,8 @@ var createCommand = cli.Command{
|
||||
if len(labelstr) > 0 {
|
||||
labels := map[string]string{}
|
||||
for _, lstr := range labelstr {
|
||||
l := strings.SplitN(lstr, "=", 2)
|
||||
if len(l) == 1 {
|
||||
labels[l[0]] = ""
|
||||
} else {
|
||||
labels[l[0]] = l[1]
|
||||
}
|
||||
k, v, _ := strings.Cut(lstr, "=")
|
||||
labels[k] = v
|
||||
}
|
||||
opts = append(opts, leases.WithLabels(labels))
|
||||
}
|
||||
|
||||
Reference in New Issue
Block a user