vmm: Remove segment_id from DeviceNode

With the segment id now encoded in the bdf it is not necessary to have
the separate field for it.

Signed-off-by: Rob Bradford <robert.bradford@intel.com>
This commit is contained in:
Rob Bradford
2021-10-26 11:19:01 +01:00
parent bad26133cb
commit 1a5a89508b
2 changed files with 6 additions and 24 deletions

View File

@@ -16,7 +16,6 @@ pub struct DeviceNode {
pub children: Vec<String>,
#[serde(skip)]
pub migratable: Option<Arc<Mutex<dyn Migratable>>>,
pub pci_segment_id: Option<u16>,
pub pci_bdf: Option<u32>,
#[serde(skip)]
pub pci_device_handle: Option<PciDeviceHandle>,
@@ -32,7 +31,6 @@ impl DeviceNode {
migratable,
pci_bdf: None,
pci_device_handle: None,
pci_segment_id: None,
}
}
}
@@ -81,20 +79,14 @@ impl DeviceTree {
pub fn pci_devices(&self) -> Vec<&DeviceNode> {
self.0
.values()
.filter(|v| {
v.pci_bdf.is_some() && v.pci_segment_id.is_some() && v.pci_device_handle.is_some()
})
.filter(|v| v.pci_bdf.is_some() && v.pci_device_handle.is_some())
.collect()
}
pub fn remove_node_by_pci_bdf(
&mut self,
pci_segment_id: u16,
pci_bdf: u32,
) -> Option<DeviceNode> {
pub fn remove_node_by_pci_bdf(&mut self, pci_bdf: u32) -> Option<DeviceNode> {
let mut id = None;
for (k, v) in self.0.iter() {
if v.pci_segment_id == Some(pci_segment_id) && v.pci_bdf == Some(pci_bdf) {
if v.pci_bdf == Some(pci_bdf) {
id = Some(k.clone());
break;
}