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aarch64: Reduce UEFI space size to 4 MiB

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UEFI need to be loaded to a flash area at the beginning of guest memory
address space. To simulate the flash, we take a piece of RAM and hide
it to the guest. As this is a temporary solution, the hiden RAM for UEFI
should be as little as possible. The size was 64 MiB, that's too much,
4 MiB is enough.

The down side of such simulation is that there is a gap (4 MiB) between
the memory size in VMM's view and that in guest's view. This is to be
fixed by implementing a flash device in future.

Signed-off-by: Michael Zhao <michael.zhao@arm.com>
This commit is contained in:
Michael Zhao
2021-06-24 09:57:01 +08:00
committed by Rob Bradford
parent d4d62fc9dc
commit 45c4d1a06e
2 changed files with 6 additions and 5 deletions
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arch/src/aarch64/layout.rs
+3 -2
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@@ -46,10 +46,11 @@
use vm_memory::GuestAddress;
/// 0x0 ~ 0x400_0000 is reserved to uefi
/// 0x0 ~ 0x40_0000 (4 MiB) is reserved to UEFI
/// UEFI binary size is required less than 3 MiB, reserving 4 MiB is enough.
pub const UEFI_START: u64 = 0x0;
pub const MEM_UEFI_START: GuestAddress = GuestAddress(0);
pub const UEFI_SIZE: u64 = 0x0400_0000;
pub const UEFI_SIZE: u64 = 0x040_0000;
/// Below this address will reside the GIC, above this address will reside the MMIO devices.
pub const MAPPED_IO_START: u64 = 0x0900_0000;