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libutil: add function to concatenate a format string in place

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Add function util_concatf() that appends the result of a format string
expansion to the end of an existing string while taking care of the
required memory allocations.

Usage example:

  char *str = NULL;

  util_concatf(&str, "list:");
  for (int i = 1; i <= 3; i++)
    util_concatf(&str, "%spart%d", (i > 1 ? "," : ""), i);
  printf("%s\n", str); /* list:part1,part2,part3 */

Reviewed-by: Jan Höppner <hoeppner@linux.ibm.com>
Signed-off-by: Peter Oberparleiter <oberpar@linux.ibm.com>
Signed-off-by: Steffen Eiden <seiden@linux.ibm.com>
This commit is contained in:
Peter Oberparleiter
2024-02-05 14:40:25 +01:00
committed by Steffen Eiden
parent 3b26f79143
commit d8e5bc07aa
3 changed files with 29 additions and 0 deletions
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8
libutil/util_libc_example.c
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@@ -40,6 +40,14 @@ int main(void)
fprintf(stderr, "result = \"%s\"\n", str);
free(str);
/* Use util_concatf() for string concatenation */
fprintf(stderr, "Try to concatenate \"list\" plus comma-separated list of numbers 1 to 3: ");
str = NULL;
util_concatf(&str, "list:");
for (int i = 1; i <= 3; i++)
util_concatf(&str, "%s%d", (i > 1 ? "," : ""), i);
fprintf(stderr, "result = %s\n", str); /* list:part1,part2,part3 */
/* One byte allocation should work */
fprintf(stderr, "Try to allocate 1 byte: ");
ptr = util_malloc(1);